Question

A seconds pendulum is taken to a place where the acceleration due to gravity falls to one fourth. How is the time period of the pendulum affected if at all? Give reason. What will be the new time period?​

Answer 1

time period = 2π√l/g

t is inversely proportional to √g

so if g is reduced by 4 times, time period will be increased by √4 = 2 times

new time period = 2×2 = 4 sec