Question

Find the zeros of the polynomial 4x^2-8x​

Answer 1

The given polynomial is as follows :-

$4 {x}^{2} - 8x$

$\rule{200}{2}$

To find :- zeroes of the polynomial.

$\rule{200}{2}$

We can say that :-

$4 {x}^{2} - 8x \\ \\ \\ = 4x(x - 2)$

$\rule{200}{2}$

To get the zeroes, we need to equate the polynomial with zero.

Hence, equating the polynomial with its zeroes :-

$\rule{200}{2}$

$4x(x - 2) = 0$

Now, here,

Either 4x will be zero or (x-2) will be zero.

Therefore :-

$4x = 0 \\ \\ x = 0$

Or,

$x - 2 = 0 \\ \\ x = 2$

$\rule{200}{2}$

Thus,

Zeroes of the polynomial are 0 and 2

$\rule{200}{2}$

Hence, solved!

Answer 2

Answer:

The zeros of the polynomial are 0 and 2

Step-by-step explanation:

There is a short method as well to solve the question but I have solved the question with the most common method which is a bit long but understood.

Compare the given equation with the general equation, i.e., ax² + bx + c.

After comparing we get:-

a = 4 ;  b = - 8 ;  c = 0

By substituting these values in the discriminant formula we will find out the zeros of the polynomial.

I have attached the complete solution. Have a look over it.