Question

a sector OAP of a circle with centre O cantaining angleO .AB perpendiculur to the radius OA and meet OPproduced at B prove that the perimeter of shaded region ( tan +sec+

Answer 1

Tan@=ab/oa
Ab = rtan@

Sec@ = ob/oa
Ob = rsec@
Now circumference of scetor
@/360 ×2×22/7×r
=@ × pie× r/180
So
Perimeter of shade region
=rtan@ + rsec@ + pie@/180 -r
=r[tan@ + sec@ + pie@/180-1]
hence proved
I hope this answer is right for you

Answer 2

Hey there

Find the attachment

Hope it helps you (or the others)