Question

A sector of a circle of radius 4cm contains an angle of 30°. Find the area of the sector.

Answer 1

Answer:

angle of sector A=30°

radius of circle=4cm

area of sector=A/360×πr²

=30/360×22/7×4×4

=1/12×22/7×4×4

=88/21

=4.2 cm² (approx.)

Answer 2

Formula used :

$Area \: of \: sector = \frac{ \alpha }{360} \pi {r}^{2}$

Given :

Angle = 30°

Radius = 4cm

Therefore,

$Area \: of \: sector = \frac{30}{360} \pi {4}^{2}$

$Area \: of \: sector = \frac{1}{12} \pi16 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{4}{3} \pi {cm}^{2}$

$Answer \: is = \frac{4}{3} \pi {cm}^{2}$