A sector Of cennal angle 216ls cut out
from a circle
of rachus 15 cm and bend
to form a
cone.
a) Find the slant height of the cone.
b) What is the height of the cone.
Answers
Answered by
1
Step-by-step explanation:
Here,
Radius of the circle, R=15 cm
When the sector is cut and its bounding radii is bent to form a cone,
Slant height of the cone, l=R=15 cm
Let r and h be the radius and height of the cone, respectively.
Again, we know that in a circle of radius R, an arc of length X subtends an angle of θ radians, then
x=Rθ
Here, the arc length will be equal to the perimeter of the base circle of the cone.
x=2πr
2πr=Rθ
R
r
=
2π
θ
⇒
15
r
=
360
216
⇒r=9 cm
Now, height of the cone can be calculated as,
h
2
=l
2
−r
2
h
2
=(15)
2
−(9)
2
h
2
=225−81
h=
144
=12 cm
Therefore,
Volume of the cone, V=
3
1
πr
2
h=
3
1
×
7
22
×81×12=1018.28 cm
3
Hence, this is the required result.
Answer
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