Math, asked by Anonymous, 5 days ago

A sector of central angle 30dgeree is cut out from a circle of radius 12 centimetres and is rolled a up into a cone. a) What is its slant height ? b) What is its radius ? c) What is its curved surface area

Answers

Answered by atharvshanker
0

Answer:

a) 12cm

b) 11 cm

c) 414.85 cm^2\\

Step-by-step explanation:

a) Slant height of cone = radius of the circle from which the cone is made

= 12cm

b) Let the radius of the cone be R cm

Curved surface area of the cone = remaining area of the circle

remaining area or the  area of the major sector of the circle = \pi r^r- \frac{30}{360} (\pi r^2)\\r=12\\\pi r^2[1-\frac{1}{12}]\\\frac{11\pi  r^2}{12}\\=> 132\pi

Curved surface area = 132\pi \\

curved surface are of a cone = \pi rl\\

\pi R(12) = 132\pi \\=> R= 11 cm

c) CSA= 132× \frac{22}{7}

          => 414.85cm^2

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