A see-saw of length 4 cm is supported at its centre. A boy weighing 4 N sits at a distance of 1 m from the centre of the see-saw. Where should a girl weighing 2 N sit ( on the other side of see-saw) so as to balance the weight of the boy?
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Answered by
1
Answer:
the answer is 2 M
Explanation:
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Answered by
2
Answer:
2 metre
Explanation:
We know that according to the principle of lever,
load x load arm = effort x effort arm
4 N x 1m = 2 N x effort arm
Thus, effort arm = 2 m
Hence, a girl must sit at a distance of 2 metre so that the see-saw will get balanced.
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