Math, asked by ViereCookil, 1 month ago

A segment of length 2 units moves parallel to the X-axis such that it subtends 90° at the origin. Then the number of points of intersection of the locus of midpoint of this segment with the curve
(y^4) + 3(x^3)y = 3(x^2)(y^2) + x(y^3) is

Answers

Answered by kgaurav8002016224
0

Answer:

 log_{e \gamma  \gamma e \sqrt{?} }(?) 225.0 \leqslant 21.j \times \frac{?}{?}

y752023fdfhb log( \beta  \alpha  \gamma e\pi \infty  \csc( \cot( \tan( \cos( \alpha  log(\% \binom{ \binom{?}{?} }{?} ) ) ) ) ) )  \times \frac{?}{?}  \times \frac{?}{?}

so,�sorry

step by step explanation is not possibul

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