Question

A self-fertilizing trihybrid plant forms [CBSE PMT 2004]
A) 8 different gametes and 16 different zygotes
B) 8 different gametes and 32 different zygotes
C) 8 different gametes and 64 different zygotes
D) 4 different gametes and 16 different zygotes

Answer 1

Explanation:

A self-fertilizing trihybrid plant forms [CBSE PMT 2004]

A) 8 different gametes and 16 different zygotes

Answer 2

Answer:

A self-fertilizing trihybrid plant forms

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ANSWER

A self-fertilising trihybrid plant will have, n = 3.

The number of combinations of gametes = 2

n

. That is equal to 2

3

= 8 combinations.

With one row or column for each allele combination, the total number of boxes in a Punnett Square equals the number of rows times the number of columns. Multi-trait Punnett squares are large. A three trait square has 64 boxes. A four trait square will thus have 256 boxes.

So, the correct answer is option A.

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