Question

A sells his car to B for 10Lakh at 10% loss Later B sells it to
A at 10% profit. What is the result of both the transactions?​

Answer 1

Answer:

first A Sells it at 1000000 with 10%loss

so fist transiction must be 1000000\100 ×10+(1000000)

=10000×10+(1000000)

=100000+1000000

=11 lakhs

second will be also same as he have sell it for 10% profit.

Answer 2

In both transaction A suffered loss of 2,11,111 Rs. and B gained 10% profit.

Step-by-step explanation:

A sells his car to B for 10,00,000 at 10% loss.

Later B sells it to A at 10% profit.

so, 10,00,000 +(10% of 10,00,000)

= 10,00,000 + 1,00,000

= 11,00,000 Rs.

Let the original price of the car was x

So,  x -(10% of x) = 10,00,000

      x - 0.10x = 10,00,000

      0.90x = 10,00,000

       x = $\frac{1000000}{0.90}$

          = 11,11,111 Rs.

A first purchased his car at 11,11,111 Rs. then sell it to B at 10,00,000 then B sells it to A at Rs. 11,00,000

Loss to A = (11,11,111 - 10,00,000) + (11,00,000 - 10,00,000)

                = 1,11,111 + 1,00,000

                = 2,11,111 Rs.

In both transaction A suffered loss of 2,11,111 Rs. and B gained 10%.

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