Question

A semicircular conducting ring is placed in yz plane in a uniform magnetic field directed along positive z-direction. An induced emf will be developed in the ring if it is moved along​

Answer 1

Refer the attachment friend ↗️↗️

Answer 2

Induced emf in the ring:

Explanation:

• Given that, a semicircular conducting ring is placed in the YZ plane in a uniform magnetic field directed along the positive z-direction.

• Lenz's law states that the electric current induced in a circuit due to a change in a magnetic field is directed to oppose the change in magnetic flux and to exert a mechanical force that is opposite to the motion.

• By Lenz's law,

$\displaystyle E = -\frac{d\phi}{dt}=-\frac{d}{dt}(BA)= -B \frac{dA}{dt} = -A\frac{dB}{dt}$

where

E = induced emf

Φ = electric flux

t = time

B = magnetic field

A = area

• So, the emf induced is in either area or magnetic field with respect to time.
• In each case, the magnetic field is parallel to the plane of the ring.
• Hence zero emf is induced in the coil.

          E = 0