Question

A semicircular sheet of metal of diameter 28 cm is rolled to form an open conical cup. Find the capacity of the cup. _______________​

Answer 1

Answer:

Step-by-step explanation:2πr = π(28/2) [Given diameter=28 so radius = 14]

r = 7cm. [This is the radius of the cone at open surface].

Slant Height = radius of the semi circle = 14 cm.

Radius of the circle at the bottom of the cone = 7 cm.

Since the height, radius of the base of the cone and the slant height forms a right angled triangle = height can be calculated = 7√3 cm.

Capacity is equal to volume of cone = πr^2h/3 =π(7)^2*(7√3/3) = 198.03π = 622.133cc.