A semicircular sheet of metal of diameter 28cm is bent to form an open conical Cup. find the capacity of the cup
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Capacity will be equal to the volume of the cone = 1/3 pi r^2 h
Capacity = 1/3 * 22 / 7 * 28 / 2 * 28
Capacity = 410.66 cm^3
Capacity = 1/3 * 22 / 7 * 28 / 2 * 28
Capacity = 410.66 cm^3
Similar questions
h = 14
Capacity = 1/3 * 22/7 * 14 * 14
Capacity = 205 . 33 cm ^3