Question

A semicircular thin sheet of metal of diameter 28cm is bent to make an open conical cup find the capacity of the cup . plz answer .

Answer 1

radius o the thin sheet =  28/2 = 14 
    lenghth of semicircular thin sheet =  2 pie r/2  = pie r
                                                     = 22/7 * 14 
                                                     = 44 cm
     semicircular thin sheet is turned into the circumference of base of cone with slant height 14cm .
    circumference = 2pie r 
                   44= 2 * 22 / 7 * r
                   r = 44 * 7 / 2 * 22 = 7cm 
   h = sqrt{ L^2 - r'^2} 
       =  sqrt { 14^2 * 7^2 }
        = sqrt { 196 - 49 }
        = sqrt { 147 }
        =  sqrt { 7 * 7 *3 }
        = 7  sqrt { 3 }

vol. of cone = 1/3 pie r'^2 h
                      = 1/3 * 22/7 * 7^2 * 7 sqrt { 3 }
                      = 1078 * 1.732 / 3

                       = 622.3653  cm^3 

Answer 2

Answer:

Step-by-step explanation:

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