Question

A seminar is being conducted by an Educational Organization, where the participants will be educators of different subjects. The number of participants in Hindi, English and Mathematics are 60, 84 and 108 respectively.(iv) The product of HCF and LCM 60 ,84 and 108 is (a) 55360 (b) 35360 (c) 45500 (d) 45360​

Answer 1

Answer:

The Number of room will be minimum if each room accomodates maximum  

number of participants. Since in each room the same number of participants  

are to be seated and all of them must be of the same subject. Therefore, the  

number of participants in each room must be the HCF of 60,84 and  

108. The prime factorisations of 60,84 and 108 are as under.

60=2  

2

×3×5,84=2  

2

×3×7 and 108=2  

2

×3  

3

 

∴ HCF of 60,84 and 108 is 2  

2

×3=12

Therefore, in each room 12 participants can be seated.

∴ Number of rooms required=  

12

Total number of participants

​

 

                                                         =  

12

60+84+108

​

=  

12

252

​

=21

Step-by-step explanation: