Physics, asked by yasinshah8432, 1 year ago

A separately-excited generator supplies 180a at 125v to a resistive load when its speed is 1200r/min. what will the current be if the speed is reduced to 1050r/min, the field remaining constant. the armature resistance is 0.06

Answers

Answered by rishi7586

0

180*125/1200=p/1050
P =250*1050/30=250*35

P = i^2r
I ^2 = 250*35/0.06=

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