The angle of elevation of an aeroplane flying horizontally at a height of 1 km is observed to be 60°and after 10 seconds it is observed to be 30°. the uniform velocity of the aeroplane in km/hr is
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Tan 60= 1/x x =1/root 3
Now tan 30 = 1/(x +v*t)
X +v*10 = root 3
10 V =root 3 - 1/root3
V =2/10root3
Now tan 30 = 1/(x +v*t)
X +v*10 = root 3
10 V =root 3 - 1/root3
V =2/10root3
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