Question

A series R-L circuit has resistance of 6 ohms and reactance of 8 ohms. The
impedance of the circuit is

O 10 ohms
O 14 ohms
O 2 ohms
O 13.43 ohms​

Answer 1

GIven,

Resistance = 6 Ω

Reactance = 8 Ω

To Find,

The impedance of the circuit.

Solution,

The formula for calculating the impedance of the circuit is

z = √(R²+X²)

where,

z is the impedance of the circuit

R is the resistance

X is the inductive reactance

So,

z = √(6²+8²)

z = √100

z = 10 Ω

Hence, the correct answer is option (a) 10 ohms.

Answer 2

Answer:

• 10 ohms

Explanation:

The impedance of the circuit is denoted by I

and R represents the resistance and L  represents inductance

In an R-L circuit the impedance of the circuit is denoted by

I = $\sqrt{R^{2}+L^{2} }$

substituting the value of

I = $\sqrt{6^{2} + 8^{2} }$

I =$\sqrt{36+84}$

I = $\sqrt{100}$

I = 10 ohms

Thus in a series R-L circuit with resistance of 6 ohms and reactance of 8 ohms. The impedance of the circuit is 10 0hms.