Question

A series rlc circuit resonate at 200 hz. If the capacitance is increased to four times, the circuit will be in resonance at

Answer 1

Resonance occurs in a series circuit when the supply frequency causes the voltages across L and C to be equal and opposite in phase

Thus far we have analysed the behaviour of a series RLC circuit whose source voltage is a fixed frequency steady state sinusoidal supply. We have also seen in our tutorial about series RLC circuits that two or more sinusoidal signals can be combined using phasors providing that they have the same frequency supply

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Answer 2

Answer:

In a series RLC circuit, the resonant frequency is given by

In a series RLC circuit, the resonant frequency is given by f = 1 / 2π√LC

In a series RLC circuit, the resonant frequency is given by f = 1 / 2π√LC

In a series RLC circuit, the resonant frequency is given by f = 1 / 2π√LC Now , the capacitance is increased to 4 times,as according to question . then the resonant will become half of the previous value.

In a series RLC circuit, the resonant frequency is given by f = 1 / 2π√LC Now , the capacitance is increased to 4 times,as according to question . then the resonant will become half of the previous value.

In a series RLC circuit, the resonant frequency is given by f = 1 / 2π√LC Now , the capacitance is increased to 4 times,as according to question . then the resonant will become half of the previous value. Hence the resonant frequency. 200 / 2 = 100