Math, asked by gousiaparveen999, 3 months ago


A set consisting of a single
nonzero vector is always _
*
O Linearly dependent
O None of these
O a Basis
O Linearly Independent​

Answers

Answered by suman8830
0

Answer:

any set consisting of a single nonzero vector is linearly independent.

Answered by AlluringNightingale
1

Answer :

Linearly independent

Explanation :

Let x be a non zero vector of the vector space V(F) and μ be any scalar such that , μx = 0

→ μ = 0 (°° x 0)

x is linearly independent vector .

Some important information :

Vector space :

(V , +) be an algebraic structure and (F , + , •) be a field , then V is called a vector space over the field F if the following conditions hold :

  1. (V , +) is an abelian group .
  2. ku ∈ V ∀ u ∈ V and k ∈ F
  3. k(u + v) = ku + kv ∀ u , v ∈ V and k ∈ F .
  4. (a + b)u = au + bu ∀ u ∈ V and a , b ∈ F .
  5. (ab)u = a(bu) ∀ u ∈ V and a , b ∈ F .
  6. 1u = u ∀ u ∈ V where 1 ∈ F is the unity .

♦ Elements of V are called vectors and the lements of F are called scalars .

♦ If V is a vector space over the field F then it is denoted by V(F) .

Linear combination :

A vector v in a vector space V is called a linear combination of the vectors v₁ , v₂ , v₃ , . . . , vₖ if v can be expressed in the form :

v = c₁v₁ + c₂v₂ + c₃v₃ + . . . + cₖvₖ

where c₁ , c₂ , c₃ , . . . , cₖ are scalars and are called weights of linear combination .

Linear dependence :

Let v₁ , v₂ , . . . , vₙ be the n non-zero vectors of a vector space V(F) . If for c₁v₁ + c₂v₂ + . . . + cₙvₙ = 0 (cᵢ ∈ F are scalars) , there exists atleast one cᵢ ≠ 0 , then v₁ , v₂ , . . . , vₙ are called linearly dependent .

♦ If the vectors v₁ , v₂ , . . . , vₙ are linearly dependent , then atleast one of these vectors can be expressed as a linear combination of the remaining vectors .

♦ Examples :

  1. (1 , 2 , 3) and (2 , 4 , 6) are linearly dependent vectors since (2 , 4 , 6) = 2(1 , 2 , 3)
  2. (1 , 3 , 4) , (1 , 2 , 3) and (0 , 1 , 1) are linearly dependent vectors since (1 , 3 , 4) = (1 , 2 , 3) + (0 , 1 , 1)
  3. (3 , 2 , 5) , (2 , 1 , 2) and (-1 , 0 , 1) are linearly dependent vectors since (3 , 2 , 5) = 2(2 , 1 , 2) + (-1 , 0 , 1) .

Linearly independence :

Let v₁ , v₂ , . . . , vₙ be the n non-zero vectors of a vector space V(F) . If for c₁v₁ + c₂v₂ + . . . + cₙvₙ = 0 (cᵢ ∈ F are scalars) , all cᵢ = 0 , then v₁ , v₂ , . . . , vₙ are called linearly independent .

♦ If the vectors v₁ , v₂ , . . . , vₙ are linearly dependent , then none of these vectors can be expressed as a linear combination of the remaining vectors .

♦ Examples :

  1. (1 , 0) and (0 , 1) are linearly independent vectors .
  2. (1 , 0 , 0) , (0 , 1 , 0) and (0 , 0 , 1) are linearly independent vectors .
  3. (1 , 2 , 3) and (0 , 3 , 4) are linearly independent vectors .
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