A set of 4 consecutive even integers has a sum of 12. What is the least of these integers?
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Answered by
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2x+(2x+2)+(2x+4)+(2x+6)=12
8x+12=12
8x=12-12
8x=0
So, X =0
Answered by
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X+X+1+X+2+X+3=12
4x+6=12
4x=6
X=3/2
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