Question

a set of 6 motors is connected in series to a 120v source drawing 1A of current. find: a) total resistance b) resistance of each motor

Answer 1

Total resistance = V/I = 120/1 = 120 Ω

Resistance of each motor = R/n = 120/6 = 20 Ω

Answer 2

Potetial difference(V) = 120v
Current (I) = 1 A
Resistance(R) =?

We know,
Ohm's law:
V = IR

Then'
R = V/I
R = 120/1
R = 120 ohm

Now' resistance in each motor:
= Resistance/no.of motor
= 120/6
= 20 ohm

Hence, Resistance = 120 ohm
Resistance in each motor = 20 ohm