A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data greater than 6.9.
Answers
Answered by
5
Solution:
z = (X-Mean)/SD
z = (6.9-5.1)/0.9 = + 2.0
According to the Empirical Rule 68-95-99.7
Mean +/- 2*SD covers 95% of the values
Percent of the values below the mean = Percent of the values above the mean = 50%
Therefore,
Required percent = 50% - 95%/2
= 50% - 47.5%
= 2.5%
z = (X-Mean)/SD
z = (6.9-5.1)/0.9 = + 2.0
According to the Empirical Rule 68-95-99.7
Mean +/- 2*SD covers 95% of the values
Percent of the values below the mean = Percent of the values above the mean = 50%
Therefore,
Required percent = 50% - 95%/2
= 50% - 47.5%
= 2.5%
Answered by
8
Answer:
Step-by-step explanation:
Solution:
z = (X-Mean)/SD
z = (6.9-5.1)/0.9 = + 2.0
According to the Empirical Rule 68-95-99.7
Mean +/- 2*SD covers 95% of the values
Percent of the values below the mean = Percent of the values above the mean = 50%
Therefore,
Required percent = 50% - 95%/2
= 50% - 47.5%
= 2.5%
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