Math, asked by sunny791, 11 months ago

a shape of a garden is rectangular in the middle and semi circuler at the end as shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is 20-(3.5+3.5)meters]​

Answers

Answered by kannaasanjay
0

Answer:

Where is the diagram..

Step-by-step explanation:


kannaasanjay: Pls send the diag..
Answered by Anonymous
2

Answer:

Perimeter of garden = 48 m

Step By  Step Explanation:

Given: Total length = 20 m

Diameter of semi circle = 7 m

So, Radius of semi circle = 7/2 = 3.5 m

Length of rectangular field = 20 – (3.5 + 3.5) = 20 – 7 = 13 m

Breadth of the rectangular field = 7 m

So, Area of rectangular field = l * b = 13 * 7 = 91 m^2

Area of two semi circles = 2 * (πr^2)/2

                                           = 2 * (22/7 * 3.5 * 3.5)/2

                                        = 22 * 0.5 * 3.5

                                        = 38.5 m^2

Area of garden = 91 + 38.5 = 129.5 m^2

Now Perimeter of two semi circles = 2 * πr

                                                             = 2 * 22/7 * 3.5

                                                              = 2 * 22 * 0.5 = 22 m

And Perimeter of garden = 22 + 13 + 13 = 48 m

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