Question

a sheet of iron is in the shape of rhombus whose diagonals are 26 and 22 what will be the cost of painting both the faces of the sheet at the rate of 1250 per 10m²​

Answer 1

Step-by-step explanation:

Diagonals : d1= 26m

d2= 22m

Area of Rhombus =

$\frac{d1 \times d2}{2} \\ \\ \frac{26 \times 22}{2} \\ \\ = 286 {m}^{2}$

Therefore area of one face of sheet = 286 sq.m

Area of two faces of sheet = 286*2= 572sq.m

Cost of painting 572sq.m =

$\frac{1250 \times 572}{10} \\ \\ = 71500$

Therefore, The cost of painting 572sq.m at Rs 10/m^2 is Rs 71500/-