Question

a sheet of paper 44 cm into 14 cm is rolled to form a cylinder into two different ways find the volume of a cylinder if the shee
t is rolled lengthwise​

Answer 1

Step-by-step explanation:

During the conversion of sheet of paper (rect.) into cylinder

length of paper becomes the height cylinder= 44cm

Diameter of cylinder will be the half of it,s breadth

= 14/2 = 7cm

So, volume =

$\pi {r}^{2} h$

$\frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 44 \\ \\ 11 \times 7 \times 22 \\ \\ 77 \times 22 \\ \\ 1694 {m}^{2}$

Answer 2

Step-by-step explanation:

During the conversion of sheet of paper (rect.) into cylinder

length of paper becomes the height cylinder= 44cm

Diameter of cylinder will be the half of it,s breadth

= 14/2 = 7cm

So, volume =

\pi {r}^{2} hπr

2

h

\begin{gathered} \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times 44 \\ \\ 11 \times 7 \times 22 \\ \\ 77 \times 22 \\ \\ 1694 {m}^{2} \end{gathered}

7

22

×

2

7

×

2

7

×44

11×7×22

77×22

1694m

2