Question

A shell is fired from a cannon with a velocity V at as angle θ with the horizontal direction.

Answer 1

Answer:

Explanation:

Given that

Angle= thetha I am taking as©

v=speed of the 1st piece

V=speed of the other piece

=>2mvcos©=m/2×vcos©+m/2×V

=>2mvcos©=m/2(vcos©+V)(on both sides M will be cancelled) then

=>2vcos©×2=(vcos© + V)

=>4vcos© - vcos© = V

=>3cos© = V

=>V =3vcos©

Hope it helps you!!??