Question

A shell is fired vertically upwards with a velocity V¹
from a trolley moving horizontally with velocity V²
A person on the ground observes the motion of the
shell as a parabola, whose horizontal range is​

Answer 1

Explanation:

Relative upward velocity of shell w.r.t to man

=upward velocity of shell - upward velocity of man

= v1 - 0 = v1 m/s

Relative horizontal velocity of shell w.r.t to man = horizontal velocity of shell - horizontal velocity of man

0 - v2 = - v2 m/s

Time of flight of shell

= 2v1/g

Horizontal range = horizontal velocity × time of flight

= -v2 × (2v1)/g

= -2(v1)(v2)/g

- ve sign indicates that displacement of shell occurs opposite to the direction of motion of man.

NOTE:

The shell undergoes only vertical motion due to vertical velocity v1. It is due to motion of man that it seems the shell is undergoing parabolic pathway due to man's velocity v2.