A shell is weighing 800kg is fired horizontally with avelocityvof 500 m/sec. From a gun weighing 50 tonne. with what initial velocity, the gun will recoil? what average force will be required to bring it to rest if it is allowed to move through one meter
Answers
Answered by
1
Explanation:
(a) By momentum conservation
700×5=v×35×103v=103100=0.1m/s
(b) K.E. goes into work done by friction
21(35×103)v2=f×x21×35×103×0.01=0.175m
Answered by
1
open sidebar
camera-retro-copy
Click Question to Get Free Answers
navigate-next
Watch 1 minute video
question-mark-1
Question From class 11 Chapter CENTRE OF MASS
A shell of mass 100 kg is fired horizontally from a cannon with a mass of
. The kinetic energy of the shell at the end of the barrel is
. The kinetic energy imparted to the cannon by the recoil is
like-icon
16.2k LIKES
view-icon
21.5k VIEWS
share-icon
21.5k SHARES
check-circle
Text Solution
Answer :
C
Solution :
m=100 kg <br>
<br> Initially system is at rest
<br>
<br>
<br>
,
Similar questions
Social Sciences,
3 months ago
English,
3 months ago
English,
3 months ago
Social Sciences,
8 months ago
English,
8 months ago