Question

A shell of mass 0.020kg is fired by a gun of mass 100 kg. If the speed of the shell is 80m/s, the recoil speed of the gun would be????​

Answer 1

$\huge\bf{Answer:-}$

According to the given question:-

• Let 100 kg be the mass of the gun and Let 0.020 kg be the mass of shell and Let 80 m/s be the Speed of the shell and Let 0 be the Initial momentum and Let mv – MV be the Final momentum.

Using formula:-

Initial momentum is equal to Final momentum

Hence, MV( – ) MV is equal to zero

$Hence \: \frac{mv}{m} = v$

Therefore,

$= \frac{0.020 \times 80}{(100 \times 1000)} = 0.016 \: is \: equal \: to \: \frac{m}{s}$

Answer 2

Answer:

Hlo mate here's your answer Hope it helps....

Mass of gun M = 100kg

mass of shell  m = 0.020kg

Velocity of shell  v = 80m/s

Recoil velocity of Gun V=?

initial velocities of both gun and shell will be zero

so, the initial momentum of the system will be zero.

According to the law of conservation of momentum,

Initial momentum = Final momentum

so,

0=mv-MV

∴v=mv/M

= $\frac {0.020\:×\:80}{100}$

​  

 

=0.016 m/s

∴recoil velocity of Gun=0.016m/s