Question

A shell of mass 0.020kg is fired by a gun of mass 100kg. If the muzzle speed of the shell rs B0m/s, what is the recoil speed of the gun?

Answer 1

given:
mass of shell(m1)=0.02kg
mass of thegun(m2)=100kg
speed of the shell(v1)=80m/s
required;recoil velocity of the gun
now from:
m1v1=-m2v2
o.02kg*80=-100v2
v2=-0.02*8/10
v2=-0.16m/s  note: * used as a multiplication sign
ANSWER:recoil velocity of the gun= -0.16m per second

Answer 2

☺Hello friend____❤

✒Your answer is here⤵

Mass of the gun, M = 100 kg

Mass of the shell, m = 0.020 kg

Muzzle speed of the shell, v = 80 m/s

Recoil speed of the gun = V

Both the gun and the shell are at rest initially.

Initial momentum of the system = 0

Final momentum of the system = mv – MV

Here, the negative sign appears because the directions of the shell and the gun are opposite to each other.

According to the law of conservation of momentum:

Final momentum = Initial momentum

mv – MV = 0

V = mv/M = ( 0.020× 80)/(100× 1000)

= 0.016 m/s

I hope, this will help you

Thank you_____❤

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