Question

A shell of mass 4 kg moving with a velocity 10 m/s vertically upward explodes into three parts at
a height 50 m from ground. After three seconds, one part of mass 2 kg reaches ground and
another part of mass 1 kg is at height 40 m from ground. The height of the third part from the
ground is: (g = 10 m/s2 ]​

Answer 1

after 3 seconds

=50+ut-1/2(g*t^2)

=50 + 10*3-1/2(10*3*3)

=35 m

H= m1H1+m2H2+m3H3/ m1+m2+m3

35= (2*0+1*40+1*H3)/4

H3=100m Ans.