Question

A shepherd has 200 sheep with him. find the number of sheep's with him after 3 years if the increase in number of sheep's is 8% every year​

Answer 1

Answer:

251 sheep's

Step-by-step explanation:

Present number of sheep's = 200 (P)

Rate of increase = 8% (R)

Time = 3 years (n)

Growth formula = P ( 1 + R/100)^n

200( 1 + 8/100)^3

200( 108/100)^3

200 × 108 × 108 × 108 / 100 × 100 × 100

=251.9424

≈251 (approximately)

So there will be approximately 251 sheep's which means that there would be a growth of 51 sheep's for 3 years at 8% per every year

Answer 2

Answer:

Step-by-step explanation:

So they have given that number of sheep is 200

with increase percentage as 8%

so 8% of 200 = 16

in three yrs it will become 16 x 3 = 48

so total number of sheep after 3 yrs = 200+48

                                                            = 248