A ship A is moving westward with a speed of 10 km/s. and ship B 100 km south of A is moving northward with a speed of 10 km/hr. The time after which distance between then becomes shortest is:
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Answer:
sin45
∘
=
OQ
PQ
PQ=100×
2
1
=50
2
m
alsoV
AB
=
V
A
2
+V
B
2
=
10
2
+10
2
=10
2
km/h
time taken of r to reach the shortest part
t=
V
AB
PQ
=
10
2
50
2
=5h
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