Question

A ship covered a distance at uniform speed . If the speed of ship would have been 6km/h faster , it would have taken 4 hours less than the scheduled time. And if the speed of ship were slower by 6 km/h, it would have taken 6 hours more than the scheduled time. Find the length of the journey.

Answer 1

Let the speed of the ship = x km / hr

distance covered = d km 

time = t1 = d/ x -----( 1 )

1 ) speed of the ship if 6km /h faster = ( x+ 6 ) km/h

time ( t2 ) = d / ( x + 6 ) ------ ( 2 )

t1 - t2 = 4

d/x - d/ ( x + 6 ) = 4

d = ( 2/3 ) [ x ( x + 6 ) ] ----( 3 )

2 ) speed of the ship 6 km / h slower than intial speed = ( x - 6 ) km / h

time = t3 = d / ( x - 6 ) h----( 4 )

t3 - t1 = 6

d/ ( x - 6 ) - d/x = 6 

d = x( x - 6 ) ----( 5 )

( 3 ) = ( 5 )

( 2/3 ) [ x ( x + 6 ) ] = x ( x - 6 )

2( x + 6 ) =3 ( x - 6 )

2x + 12 = 3x - 18

12 + 18 = 3x - 2x

x = 30 km/h

put x value in equation ( 5 ) ,

d = x ( x - 6 )

= 30 ( 30 - 6 )

= 30 × 24

= 720 km

I hope this helps you.

Answer 2

I have already answered this question.

https://brainly.in/question/2124163