A ship floating in the Pacific Ocean where the temperature is 23.4 C, a balloon is filled with 2L of air. When this ship reaches the Indian Ocean, where the temperature is 26.1 C, what will be its volume ?
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Answers
Answered by
1
Answer with explanation:
• Given that,
V1 = 2L
T2 = 26.1 + 273 = 299.1K
T1 = (23.4 + 273)K
T1 = 296.4K
• According to Charles Law,
V1/T1 = V2/T2
V2 = V1T2/T1
V2 = 2L * 299.1K/296.4K
V2 = 2L * 1.009
V2 = 2.018L
I hope this is helpful!
Answered by
0
Explanation:
V
1
=2L, T
1
=273+23.4=296.4K
V
2
=?, T
2
=273+26.1=299.1K
According to charles law
V
2
V
1
=
T
2
T
1
or, V
2
=
T
1
V
1
T
2
substuting the values, we have
V
2
=
296.4K
2L×299.1K
2L×1.009=2.018L
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