Physics, asked by hanirvesh4704, 10 months ago

A ship is moving at a speed of 56 km/h. One minute later, it is moving at 58 km/h. What is its acceleration?

Answers

Answered by Anonymous
30

Answer:

0.009259 m/s²

Explanation:

Given :

  • Initial velocity = u = 56 km/hr

  • Final velocity = v = 58 km/hr

  • Time taken = t = 1 minute = 60 seconds

To find :

  • Acceleration of the ship with which it is moving

u = 56×5/18 = 140/9

v = 58×5/18 = 145/9

t = 60 seconds

Acceleration = (v-u) / t

Acceleration = (145/9 - 140/9)/60

Acceleration = (5/9)/60

Acceleration = 5/9×1/60

Acceleration = 5/540 m/s²

Acceleration = 0.009259 m/s²

The acceleration of the ship is equal to 0.009259 m/s²


Anonymous: Perfect!
Answered by Anonymous
13

{ \huge{ \bold{ \underline{ \underline{ \pink{Question:-}}}}}}

A ship is moving at a speed of 56 km/h. One minute later, it is moving at 58 km/h. What is its acceleration?

_______________

{ \huge{ \bold{ \underline{ \underline{ \purple{Answer:-}}}}}}

Given : -

  • Final Velocity(v) = 58 km/h
  • Initial Velocity(u) = 56 km/h
  • Time Taken(t) = 1 min. (60 seconds)

To Find : -

  • Acceleration = ?

On Calculating : -

➫u = 56 × 5/18 = 140/9

➫v = 58 × 5/18 = 145/9

➫t = 60 sec.

Formula Used : -

\leadsto\sf{{ \small{ \bold{ \bold{ \bold{ \red{Acceleration=\dfrac{(v-u)}{t}}}}}}}}

Now ,

➫ a = (145/9 - 140/9)/60

➫ a = (5/9)/60

➫ a = 5/9 × 1/60

➫ a = 5/540 m/s²

➫ a = (5/9)/60

➫ a = 5/9 × 1/60

➫ a = 5/540 m/s²

\leadsto\sf{{ \large{ \boxed{ \bold{ \bold{ \orange{0.009259{m/s}^{2}}}}}}}}

➴So , the acceleration of the ship is 0.00925 ..


Anonymous: Good!!!
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