Question

A ship is moving at a speed of 56km/h. One second later it is moving at 58km/h. What is its acceleration?

Answer 1

u = 56 km/h = 56 * 1000/3600 = 15.55 m/s
v = 58 km/h = 58 * 1000/3600 = 16.11 m/s
t = 1 s

Therefore, acceleration = (v-u)/t = (16.11 - 15.55) / 1
                                               = 0.56 m/s^2 

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

$\text{At\;first\; we\; have\; to\; convert\; unit \;of \;given\; quantities\; into\; SI\; units}$

★Here

1km = 1000m

1h = 3600s

$\huge{\boxed{Therefore}}$

u = 56 km/h

${\boxed{\sf\:{Convert\;it\; into\; m/s }}}$

$\tt{\rightarrow\dfrac{56km}{1h}}$

$\tt{\rightarrow\dfrac{56\times 1000m}{1\times 3600s}}$

u = 15.55 m/s

v = 58km/h

${\boxed{\sf\:{Convert\;it\; into\; m/s }}}$

$\tt{\rightarrow\dfrac{58km}{1h}}$

$\tt{\rightarrow\dfrac{58\times 1000m}{1\times 3600s}}$

= 16.11 m/s

Time taken (t) = 1 second

★Now

★Acceleration :-

$\tt{\rightarrow a =\dfrac{v-u}{t}}$

$\tt{\rightarrow\dfrac{16.11-15.55}{1s}}$

$\tt{\rightarrow\dfrac{0.56}{1s}}$

= 0.56 m/s²

${\boxed{\sf\:{Acceleration\;of\; ship = 0.56 \;m/s^{2}}}}$

$\boxed{\begin{minipage}{11 cm} Additional Information \\ \\ \ Distance = Speed\times Time \\ \\ Displacement=Velocity\times time \\ \\ Average\; Speed = \dfrac{Initial\:\:Speed+Final\:\:Speed}{2} \end{minipage}}$