A ship is moving at a speed of 56km/h . One second later , it is moving at 58km/h . What is it's acceleration And distance travelled?
Answers
Answered by
1
u=56 km/h
v=58km/h
t=1sec.
a=v-u/t
=58-56/1
a=2ms*-2
d=1/2ut+at2
=1/2×56×1+2×1×1
=28+2
d=30m
v=58km/h
t=1sec.
a=v-u/t
=58-56/1
a=2ms*-2
d=1/2ut+at2
=1/2×56×1+2×1×1
=28+2
d=30m
yogesh130:
Its wrong I guess
so what is correct answer
But thanks for ur help
ok
I know the acceleration but not the distance the acceleration is 0.55m/s
how
U=56*5/18=15.55m/s
Then v= 16.11m/s. a=v-u/t
a=16.11-15.55/1=0.55m/s^2
Answered by
0
a=v^2-u^2/2
58^2 - 56^2 /2
=3364-3136
=228/2
=114m/s
s=ut+1/2at^2
56*1+1/2*114*1*1
113m
It's also wrong but thanx
v-u/t =58-56/1=2m/s distance =57m
Similar questions