a ship is moving at a speed of 56km/hr. One second later , it is moving at a speed of 58km/hr. what is its acceleration
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Answered by
4
u = 56 km/h = (56*5)/18 m/s = 15.55 m/s
v = 58 km/h = (58*5)/18 m/s = 16.11 m/s
time, t = 1s
acceleration = (v-u)/t = (16.11-15.55)/1 = 0.55 m/s²
v = 58 km/h = (58*5)/18 m/s = 16.11 m/s
time, t = 1s
acceleration = (v-u)/t = (16.11-15.55)/1 = 0.55 m/s²
Answered by
4
initial velocity = u = 56 kmph
v = final velocity = 58 kmph
change in velocity = v - u = 2 kmph = 2 * 5/18 = 5/9 m/sec
time duration t = 1 second.
acceleration = a = (v - u) / t = 5/9 m/sec² = 0.5556 m/sec²
v = final velocity = 58 kmph
change in velocity = v - u = 2 kmph = 2 * 5/18 = 5/9 m/sec
time duration t = 1 second.
acceleration = a = (v - u) / t = 5/9 m/sec² = 0.5556 m/sec²
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