Question

relative density of silver is 10.8 . find its density in SI unit

Answer 1

RELATIVE DENSITY OF SILVER  =  $\frac{DENSITYOF SILVER}{DENSITY OF WATER}$

THEREFORE DENSITY OF SILVER = RELATIVE DENSITY X DENSITY OF WATER

WE ALREADY KNOW THE DENSITY OF WATER IS $10^{3}$ kg $m^{-3}$

SO DENSITY = 10.8 X $10^{3}$

SI UNIT OF DENSITY = kg/m³
SO DENSITY OF SILVER = 10.8 X 10³ kg m-³

Answer 2

Relative density = Density relative to water 
      Density of silver = relative density * density of water
                          = 10.8 * 1 gm/cm³ = 10.8 gm/cm³
                  in SI units,  10.8 * 1000 kg/m³ = 10, 800 kg / m³