A ship moves at a speed of 56km/h. One second later,is moving at 58km/h. What is the acceleration in m/s2
Answers
Answered by
4
Given t = 1 sec.
Given u = 56 km/hr = 56 * 5/18
= 15.56 m/s.
Given v = 58 km/hr = 58 * 5/18
= 16.11.
We know that Acceleration a = (v-u)/t
= 16.11 - 15.56
= 0.55 m/s^2.
Given u = 56 km/hr = 56 * 5/18
= 15.56 m/s.
Given v = 58 km/hr = 58 * 5/18
= 16.11.
We know that Acceleration a = (v-u)/t
= 16.11 - 15.56
= 0.55 m/s^2.
Answered by
3
58km/h=58*(5/18)m/s - eqn1
56km/h=56*(5/18)m/s - eqn2
accln.= (eqn1 - eqn2)/time
= 2*(5/18)....(as time is 1sec)
= 5/9m/s2
accln.= 0.5556m/s2.
56km/h=56*(5/18)m/s - eqn2
accln.= (eqn1 - eqn2)/time
= 2*(5/18)....(as time is 1sec)
= 5/9m/s2
accln.= 0.5556m/s2.
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