a ship of mass 2 x 10^7 is at rest on applying a force of 25x 10^5 N it is displaced through 25m the speed of ship after displacement is
Answers
Given data :
- Mass of the ship, m = 2 * 10⁷ kg
- Force acting on the ship, F = 25 * 10⁵ N
- Displacement of the ship, s = 25 m
- initial velocity of the ship, u = 0
- Speed/final velocity of ship after displacement, v = ?
Solution : firstly we have to find out acceleration of the ship.
Now,
⟹ Force = Mass * Acceleration
⟹ Acceleration = Force/Mass
⟹ Acceleration = (25 * 10⁵)/(2 * 10⁷)
⟹ Acceleration = 12.5 * 10^( - 2 )
⟹ Acceleration = 12.5/100
⟹ Acceleration = 0.125 m/s²
Here, Acceleration, a = 0.125 m/s²
Now, we use kinematical equation
⟹ v² = u² + 2 * a * s
⟹ v² - u² = 2 * a * s
⟹ v² - 0 = 2 * 0.125 * 25
⟹ v² = 0.25 * 25
⟹ v² = 6.25
⟹ v = √6.25
⟹ v = 2.5 m/s
Answer : Speed of the ship after displacement is 2.5 m/s.
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