Question

A ship of mass 3×10^7kg and initially at rest can be pulled through a distance of 3m by means of a force of 5×10^4N . The water resistance is negligible. Find the speed attained by the ship.

Answer 1

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Answer 2

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Given,

$m =3×10^{7}$ kg
$s = 3$ m
$F = 5 × 10^{4}$ N
As initally it is at rest $u = 0$


----- First Find 'a'

We have,
$F = ma$

$5 × 10^{4} =3×10^{7} × a$

=> $a = \frac{5×10^{4}}{3×10^{7}}$

=> $a = \frac{5}{3}× 10^{-3}$



---- Now Find 'v'

We have,
$v^{2}-u^{2}= 2as$

As u = 0
$v^{2}= 2as$

$v^{2} = 2 × \frac{5}{3}× 10^{-3} × 3$

=> $v^{2} = 10 × 10^{-3}$

=> $v^{2} = 10^{-2}$

=> $v = \sqrt{10^{-2}}$

=> $v = 10^{-1}$

=> $v = 0.1\: m/s$