Question

A ship of mass 3×10^7kg initially at rest is pulled by a force of 5×10^4 through a distance of 3 m . Assuming resistance due to water is negligible . Then the speed of ship is :

Answer 1

Answer:

m =3×10^7kg

u=0

f=5×10^4N

s=3m

v=?

according to equation f=ma

a=f/m=5×10^4N/3×10^7kg

now by,v^2=u^2+2as

v^2=0+2×5×10^4/3×10^7×3

v^2=2×5×10^4-7=

v^2=10×10^-3

v^2=10^-2

v=

$\sqrt{10^ { - 2} }$=0.1m/s