A ship sends out ultrasound, produced by transmitter that returns from the sea-bed and detected after 3 sec. If the speed
of ultrasound through sea water is 1530 m/s., find the distance of the sea-bed from the ship.
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SINCE IT IS SENT AND RECEIVED BACK IN 3 SEC , IT COVERS DOUBLE THE DISTANCE FROM SEABED .
HENCE,WE NEED TO FIND 2d.
2d = speed * time
=1530*3= 4590
therefore ,
d = 4590/ 2 =2295 m
arpit.
HENCE,WE NEED TO FIND 2d.
2d = speed * time
=1530*3= 4590
therefore ,
d = 4590/ 2 =2295 m
arpit.
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