A ship sends out ultrasound that return from the seabed and is detected after 3.42s. if the speed of ultrasound through sea water is 1531m/s, what is the distance of the seabed from the ship?
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SINCE IT IS SENT AND RECEIVED BACK IN 3.42 SEC , IT COVERS DOUBLE THE DISTANCE FROM SEABED .
HENCE,WE NEED TO FIND 2d.
2d = speed * time
=1531*3.42 = 5236.02
therefore ,
d = 5236.02/ 2 =2618 m
HENCE,WE NEED TO FIND 2d.
2d = speed * time
=1531*3.42 = 5236.02
therefore ,
d = 5236.02/ 2 =2618 m
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