A ship sends out ultrasound that returns from the sea bed and is detected after 3.42 s. If the speed of ultrasound
through sea water is 1531 ms"1
what is the distance of the sea bed from the ship?
Answers
Answered by
8
2d= v×t
v= 1531m/s
t= 3.42s
2d= 1531× 3.42
2d= 5236.02
d= 5236.02÷ 2
d= 2618.01
hope this helps you...
pl mark it as a brainliest answer...
v= 1531m/s
t= 3.42s
2d= 1531× 3.42
2d= 5236.02
d= 5236.02÷ 2
d= 2618.01
hope this helps you...
pl mark it as a brainliest answer...
Answered by
4
Hey there !
Here ,
Time = t = 3.42 seconds
Speed of water = v = 1531 m/s
Distance of the sea bed from the ship = d
2d = distance traveled by the echo
Here is a formula to calculate the distance :-
2d = v × t
= 1531 × 3.42
= 5236.02 m
d = 5236.02 ÷ 2
= 2618.01 m
Hope this Helped You !
Here ,
Time = t = 3.42 seconds
Speed of water = v = 1531 m/s
Distance of the sea bed from the ship = d
2d = distance traveled by the echo
Here is a formula to calculate the distance :-
2d = v × t
= 1531 × 3.42
= 5236.02 m
d = 5236.02 ÷ 2
= 2618.01 m
Hope this Helped You !
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