a ship sends out ultrasound that returns from the Sea bed and are deducted after 3.42 s. if the speed of ultrasound through sea water is 1531 m/swhat is the distance of the sea bed from the ship
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here is your answer
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given
➡time between transmission ans detection t=3.42s
➡speed of ultra sound is sea water
➡v=1531m/s
➡distance travelled by ultra sound
➡2×depth of the sea =2d
➡where d is depth of the sea
➡2d=speed of sound ×time
➡1531m/s×3.42s=5236m
➡d=5236m/2=2618m
➡thus the distance of the sea bed from the ship is 2618m or 2.62km
=========================
here is your answer
=================
given
➡time between transmission ans detection t=3.42s
➡speed of ultra sound is sea water
➡v=1531m/s
➡distance travelled by ultra sound
➡2×depth of the sea =2d
➡where d is depth of the sea
➡2d=speed of sound ×time
➡1531m/s×3.42s=5236m
➡d=5236m/2=2618m
➡thus the distance of the sea bed from the ship is 2618m or 2.62km
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