A ship sends out ultrasound that returns from the seabed and is detected after 3.42 s. If the speed of ultrasound through seawater is 1531 m/s . What is the distance of the seabed from the ship?
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time = 3.42sec.
so the time taken to reach the sea bed is 3.42/2
t1=1.71sec.
so the distance covered d=v*t
d=1531*1.71
d=2618.01m
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Refer to the Attachment.
Mr.Legend
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